1. Write a program to
find factorial of the given number.
Recursion: A function
is called'recursive 'if a statement within the body of a function
calls the same function. It
is also called'circular
definition '. Recursion is thus a process of defining something in
terms of itself.
Program: To calculate
the factorial value using recursion.
#include
int fact(int n);
int main(){
int x, i;
printf("En ter a
value for x: \n");
scanf("%d"
,&x);
i = fact(x);
printf("\n
Factorial of %d is %d", x, i);
return 0;
}int fact(int n){
/* n=0 indicates a
terminatin g condition */
if (n
return (1);
}else{
/* function calling
itself */
return (n * fact(n -
1));
/*n*fact(n -1) is a
recursive expression */
}
}
Output:
Enter a value for x:
4
Factorial of 4 is 24
Explanatio n:
fact(n) = n * fact(n-1)
If n=4
fact(4) = 4 * fact(3)
there is a call to fact(3)
fact(3) = 3 * fact(2)
fact(2) = 2 * fact(1)
fact(1) = 1 * fact(0)
fact(0) = 1
fact(1) = 1 * 1 = 1
fact(2) = 2 * 1 = 2
fact(3) = 3 * 2 = 6
Thus fact(4) = 4 * 6 =
24
Terminating condition(
n
infinite loop.)
2. Write a program to
check whether the given number is even or odd.
Program:
#include
int main(){
int a;
printf("En ter a:
\n");
scanf("%d"
,&a);
/* logic */
if (a % 2 == 0){
printf("Th e given
number is EVEN\n");
}
else{
printf("Th e given
number is ODD\n");
}
return 0;
}
Output:
Enter a: 2
The given number is
EVEN
Explanatio n with
examples:
Example 1: If entered
number is an even number
Let value of'a'entered
is 4
if(a%2==0) then a is an
even number, else odd.
i.e. if(4%2==0) then 4
is an even number, else odd.
To check whether 4 is
even or odd, we need to calculate (4%2).
/* % (modulus) implies
remainder value. */
/* Therefore if the
remainder obtained when 4 is divided by 2 is 0, then 4 is even. */
4%2==0 is true
Thus 4 is an even
number.
Example 2: If entered
number is an odd number.
Let value of'a'entered
is 7
if(a%2==0) then a is an
even number, else odd.
i.e. if(7%2==0) then 4
is an even number, else odd.
To check whether 7 is
even or odd, we need to calculate (7%2).
7%2==0 is false /*
7%2==1 condition fails and else part is executed */
Thus 7 is an odd number.
3. Write a program to
swap two numbers using a temporary variable.
Swapping interchang es
the values of two given variables.
Logic:
step1: temp=x;
step2: x=y;
step3: y=temp;
Example:
if x=5 and y=8,
consider a temporary variable temp.
step1: temp=x=5;
step2: x=y=8;
step3: y=temp=5;
Thus the values of the
variables x and y are interchang ed.
Program:
#include
int main(){
int a, b, temp;
printf("En ter the
value of a and b: \n");
scanf("%d
%d",&a,&b);
printf("Be fore
swapping a=%d, b=%d \n", a, b);
/*Swapping logic */
temp = a;
a = b;
b = temp;
printf("Af ter
swapping a=%d, b=%d", a, b);
return 0;
}
Output:
Enter the values of a
and b: 2 3
Before swapping a=2,
b=3
After swapping a=3, b=2
4. Write a program to
swap two numbers without using a temporary variable.
Swapping interchang es
the values of two given variables.
Logic:
step1: x=x+y;
step2: y=x-y;
step3: x=x-y;
Example:
if x=7 and y=4
step1: x=7+4=11;
step2: y=11-4=7;
step3: x=11-7=4;
Thus the values of the
variables x and y are interchang ed.
Program:
#include
int main(){
int a, b;
printf("En ter
values of a and b: \n");
scanf("%d
%d",&a,&b);
printf("Be fore
swapping a=%d, b=%d\n", a,b);
/*Swapping logic */
a = a + b;
b = a - b;
a = a - b;
printf("Af ter
swapping a=%d b=%d\n", a, b);
return 0;
}
Output:
Enter values of a and
b: 2 3
Before swapping a=2,
b=3
The values after swapping are a=3 b=2
5. Write a program to
swap two numbers using bitwise operators.
Program:
#include
int main(){
int i = 65;
int k = 120;
printf("\n value
of i=%d k=%d before swapping", i, k);
i = i ^ k;
k = i ^ k;
i = i ^ k;
printf("\n value
of i=%d k=%d after swapping", i, k);
return 0;
}
Explanatio n:
i = 65; binary
equivalent of 65 is 0100 0001
k = 120; binary
equivalent of 120 is 0111 1000
i = i^k;
i...0100 0001
k...0111 1000
---------
val of i = 0011 1001
---------
k = i^k
i...0011 1001
k...0111 1000
---------
val of k = 0100 0001
binary equivalent of this is 65
---------( that is the
initial value of i)
i = i^k
i...0011 1001
k...0100 0001
---------
val of i = 0111 1000
binary equivalent of this is 120
--------- (that is the
initial value of k)
6. Write a program to
find the greatest of three numbers.
Program:
#include
int main(){
int a, b, c;
printf("En ter
a,b,c: \n");
scanf("%d %d
%d",&a,&b,&c);
if (a>b&&a>c){
printf("a is
Greater than b and c");
}
else if (b>a&&b>c){
printf("b is
Greater than a and c");
}
else if (c>a&&c>b){
printf("c is
Greater than a and b");
}
else{
printf("al l are
equal or any two values are equal");
}
return 0;
}
Output:
Enter a,b,c: 3 5 8
c is Greater than a and
b
Explanatio n with
examples:
Consider three numbers
a=5,b=4,c= 8
if(a>b&&a>c)
then a is greater than b and c
now check this
condition for the three numbers 5,4,8 i.e.
if(5>4&&5>8)
/* 5>4 is true but 5>8 fails */
so the control shifts
to else if condition
else if(b>a&&b>c)
then b is greater than a and c
now checking this
condition for 5,4,8 i.e.
else if(4>5&&4>8)
/ * both the conditions fail */
now the control shifts
to the next else if condition
else if(c>a&&c>b)
then c is greater than a and b
now checking this
condition for 5,4,8 i.e.
else if(8>5&&8>4)
/ * both conditions are satisfied */
Thus c is greater than a and b.
7. Write a program to
find the greatest among ten numbers.
Program:
#include
int main(){
int a[10];
int i;
int greatest;
printf("En ter ten
values:");
//Store 10 numbers in
an array
for (i = 0; i<10;
i++){
scanf("%d"
,&a[i]);
}
//Assume that a[0] is
greatest
greatest = a[0];
for (i = 0; i<10;
i++){
if (a[i]>greatest){
greatest = a[i];
}
}
printf("\n
Greatest of ten numbers is %d", greatest);
return 0;
}
Output:
Enter ten values: 2 53
65 3 88 8 14 5 77 64 Greatest of ten numbers is 88
Explanatio n with
example:
Entered values are 2,
53, 65, 3, 88, 8, 14, 5, 77, 64
They are stored in an
array of size 10. let a[] be an array holding these values.
/* how the greatest
among ten numbers is found */
Let us consider a
variable'greatest' . At the beginning of the loop, variable'greatest'
is assinged with the value of
first element in the
array greatest=a [0]. Here variable'greatest' is assigned 2 as
a[0]=2.
Below loop is executed
until end of the array'a[]';.
for(i=0; i
{
if(a[i]>gr eatest)
{
greatest= a[i];
}
}
For each value of'i',
value of a[i] is compared with value of variable'greatest' . If any
value greater than the value
of'greatest' is
encountere d, it would be replaced by a[i]. After completion
of'for'loop, the value of variable
'greatest' holds the
greatest number in the array. In this case 88 is the greatest of all
the numbers.
8. Write a program to
check whether the given number is a prime.
A prime number is a
natural number that has only one and itself as factors. Examples: 2,
3, 13 are prime
numbers.
Program:
#include
main(){
int n, i, c = 0;
printf("En ter any
number n: \n");
scanf("%d"
,&n);
/*logic*/
for (i = 1; i
if (n % i == 0){
c++;
}
}
if (c == 2){
printf("n is a
Prime number");
}
else{
printf("n is not a
Prime number");
}
return 0;
}
Output:
Enter any number n: 7
n is Prime
Explanatio n with
examples:
consider a number n=5
for(i=0;i
i.e. for(i=0;i
1st iteration: i=1;i
here i is incremente d
i.e. i value for next iteration is 2
now if(n%i==0) then c
is incremente d
i.e.if(5%1 ==0)then c
is incremente d, here 5%1=0 thus c is incremente d.
now c=1;
2nd iteration: i=2;i
here i is incremente d
i.e. i value for next iteration is 3
now if(n%i==0) then c
is incremente d
i.e.if(5%2 ==0) then c
is incremente d, but 5%2!=0 and so c is not incremente d, c remains 1
c=1;
3rd iteration: i=3;i
here i is incremente d
i.e. i value for next iteration is 4
now if(n%i==0) then c
is incremente d
i.e.if(5%3 ==0) then c
ic incremente d, but 5%3!=0 and so c is not incremente d, c remains 1
c=1;
4th iteration: i=4;i
here i is incremente d
i.e. i value for next iteration is 5
now if(n%i==0) then c
is incremente d
i.e. if(5%4==0) then c
is incremente d, but 5%4!=0 and so c is not incremente d, c remains 1
c=1;
5th iteration: i=5;i
here i is incremente d
i.e. i value for next iteration is 6
now if(n%i==0) then c
is incremente d
i.e. if(5%5==0) then c
is incremente d, 5%5=0 and so c is incremente d.
i.e. c=2
6th iteration: i=6;i
here i value is 6 and 6
now if(c==2) then n is
a prime number
we have c=2 from the
5th iteration and thus n=5 is a Prime number.
9. Write a program to
check whether the given number is a palindromi c number.
If a number, which when
read in both forward and backward way is same, then such a number is
called a
palindrome number.
Program:
#include
int main(){
int n, n1, rev = 0,
rem;
printf("En ter any
number: \n");
scanf("%d"
,&n);
n1 = n;
/* logic */
while (n>0){
rem = n % 10;
rev = rev * 10 + rem;
n = n / 10;
}
if (n1 == rev){
printf("Gi ven
number is a palindromi c number");
}
else{
printf("Gi ven
number is not a palindromi c number");
}
return 0;
}
Output:
Enter any number: 121
Given number is a
palindrome
Explanatio n with an
example:
Consider a number
n=121, reverse=0, remainder;
number=121
now the while loop is
executed /* the condition (n>0) is satisfied */
/* calculate remainder
*/
remainder of 121
divided by 10=(121%10 )=1;
now reverse=(r
everse*10) +remainder
=(0*10)+1 / * we have
initialized reverse=0 */
=1
number=num ber/10
=121/10
=12
now the number is 12,
greater than 0. The above process is repeated for number=12.
remainder= 12%10=2;
reverse=(1 *10)+2=12;
number=12/ 10=1;
now the number is 1,
greater than 0. The above process is repeated for number=1.
remainder= 1%10=1;
reverse=(1 2*10)+1=12
1;
number=1/ 10 / * the
condition n>0 is not satisfied,co ntrol leaves the while loop */
Program stops here. The
given number=121 equals the reverse of the number. Thus the given
number is a
palindrome number.
10.Write a program to
check whether the given string is a palindrome .
Palindrome is a string,
which when read in both forward and backward way is same.
Example: radar, madam,
pop, lol, rubber, etc.,
Program:
#include
#include
int main(){
char string1[20 ];
int i, length;
int flag = 0;
printf("En ter a
string: \n");
scanf("%s" ,
string1);
length = strlen(str
ing1);
for(i=0;i<length
;i++){
if(string1 [i] !=
string1[le ngth-i-1]) {
flag = 1;
break;
}
}
if (flag){
printf("%s is not
a palindrome \n", string1);
}
else{
printf("%s is a
palindrome \n", string1);
}
return 0;
}
Output:
Enter a string: radar
"radar"is a
palindrome
Explanatio n with
example:
To check if a string is
a palindrome or not, a string needs to be compared with the reverse
of itself.
Consider a palindrome
string:"radar",
---------- ----------
-------
index: 0 1 2 3 4
value: r a d a r
---------- ----------
-------
To compare it with the
reverse of itself, the following logic is used:
0th character in the
char array, string1 is same as 4th character in the same string.
1st character is same
as 3rd character.
2nd character is same
as 2nd character.
. . . .
ith character is same
as'length-i- 1'th character.
If any one of the above
condition fails, flag is set to true(1), which implies that the
string is not a palindrome .
By default, the value of flag is false(0). Hence, if all the
conditions are satisfied, the string is a palindrome .
11.Write a program to
generate the Fibonacci series.
Fibonacci series: Any
number in the series is obtained by adding the previous two numbers
of the series.
Let f(n) be n'th term.
f(0)=0;
f(1)=1;
f(n)=f(n-1 )+f(n-2);
(for n>=2)
Series is as follows
011
(1+0)
2 (1+1)
3 (1+2)
5 (2+3)
8 (3+5)
13 (5+8)
21 (8+13)
34 (13+21)
...and so on
Program: to generate
Fibonacci Series(10 terms)
#include
int main(){
//array fib stores
numbers of fibonacci series
int i, fib[25];
// initialized first
element to 0
fib[0] = 0;
// initialized second
element to 1
fib[1] = 1;
//loop to generate ten
elements
for (i = 2; i<10;
i++){
//i'th element of
series is equal to the sum of i-1'th element and i-2'th element.
fib[i] = fib[i - 1] +
fib[i - 2];
}
printf("Th e
fibonacci series is as follows \n");
//print all numbers in
the series
for (i = 0; i<10;
i++){
printf("%d \n",
fib[i]);
}
return 0;
}
Output:
The fibonacci series is
as follows
01123581
3
21
34
Explanatio n:
The first two elements
are initialize d to 0, 1 respective ly. Other elements in the series
are generated by looping
and adding previous two
numbes. These numbers are stored in an array and ten elements of the
series are
printed as output.
12.Write a program to
print"Hello World"without using semicolon anywhere in the
code.
Generally when we use
printf("") statement, we have to use a semicolon at the
end. If printf is used inside an if
Condition, semicolon
can be avoided.
Program: Program to
print something without using semicolon (;)
#include
int main(){
//printf returns the
length of string being printed
if (printf("H ello
World\n")) //prints Hello World and returns 11
{
//do nothing
}
return 0;
}
Output:
Hello World
Explanatio n:
The if statement checks
for condition whether the return value of printf("He llo World")
is greater than 0. printf
function returns the
length of the string printed. Hence the statement if (printf("H
ello World")) prints the string
"Hello World".
13.Write a program to
print a semicolon without using a semicolon anywhere in the code.
Generally when use
printf("") statement we have to use semicolon at the end.
If we want to print a
semicolon, we use the statement: printf(";" );
In above statement, we
are using two semicolons . The task of printing a semicolon without
using semicolon anywhere in the code can be accomplish ed by using
the ascii value of';'which is equal to 59.
Program: Program to
print a semicolon without using semicolon in the code.
#include
int main(void) {
//prints the character
with ascii value 59, i.e., semicolon
if (printf("%
c\n", 59)){
//prints semicolon
}
return 0;
}
Output:
;
Explanatio n:
If statement checks
whether return value of printf function is greater than zero or not.
The return value of function
call printf("%c
",59) is 1. As printf returns the length of the string printed.
printf("%c ",59) prints ascii value that
correspond s to 59, that is semicolon( .
14.Write a program to
compare two strings without using strcmp() function.
strcmp() function
compares two strings lexicograp hically. strcmp is declared in
stdio.h
Case 1: when the
strings are equal, it returns zero.
Case 2: when the
strings are unequal, it returns the difference between ascii values
of the characters that differ.
a) When string1 is
greater than string2, it returns positive value.
b) When string1 is
lesser than string2, it returns negative value.
Syntax:
int strcmp (const char
*s1, const char *s2);
Program: to compare two
strings.
#include
#include
int cmpstr(cha r
s1[10], char s2[10]);
int main(){
char arr1[10]
="Nodalo";
char arr2[10]
="nodalo";
printf("%d",
cmpstr(arr 1, arr2));
// cmpstr() is
equivalent of strcmp()
return 0;
}/
/s1, s2 are strings to
be compared
int cmpstr(cha r
s1[10], char s2[10]){
//strlen function
returns the length of argument string passed
int i = strlen(s1) ;
int k = strlen(s2) ;
int bigger;
if (i<k){
bigger = k;
}
else if (i>k){
bigger = i;
}
else{
bigger = i;
}
//loops'bigger'times
for (i = 0; i<bigger;
i++){
// if ascii values of
characters s1[i], s2[i] are equal do nothing
if (s1[i] == s2[i]){
}
//else return the ascii
difference
else{
return (s1[i] - s2[i]);
}
}
//return 0 when both
strings are same
//This statement is
executed only when both strings are equal
return (0);
}
Output:
-32
Explanatio n:
cmpstr() is a function
that illustrate s C standard function strcmp(). Strings to be
compared are sent as arguments
to cmpstr().
Each character in
string1 is compared to its correspond ing character in string2. Once
the loop encounters a
differing character in the strings, it would return the ascii
difference of the differing characters and exit.
15.Write a program to
concatenat e two strings without using strcat() function.
strcat(str ing1,strin
g2) is a C standard function declared in the header file string.h
The strcat() function
concatenat es string2, string1 and returns string1.
Program: Program to
concatenat e two strings
#include
#include
char *strct(cha r *c1,
char *c2);
char *strct(cha r *c1,
char *c2){
//strlen function
returns length of argument string
int i = strlen(c1) ;
int k = 0;
// loops until null is
encountered and appends string c2 to c1
while (c2[k] !='\0'){
c1[i + k] = c2[k];
k++;
}
return c1;
}
int main(){
char string1[15 ]
="first";
char string2[15 ]
="second";
char *finalstr;
printf("Be fore
concatenat ion:"
"\n string1 = %s
\n string2 = %s", string1, string2);
// addresses of
string1, string2 are passed to strct()
finalstr = strcat(str
ing1, string2);
printf("\n After
concatenat ion:");
//prints the contents
of string whose address is in finalstr
printf("\n
finalstr = %s", finalstr);
//prints the contents
of string1
printf("\n string1
= %s", string1);
//prints the contents
of string2
printf("\n string2
= %s", string2);
return 0;
}
Output:
Before concatenat ion:
string1 = first
string2 = second
After concatenat ion:
finalstr = firstsecon d
string1 = firstsecon d
string2 = second
Explanatio n:
string2 is appended at
the end of string1 and contents of string2 are unchanged.
In strct() function,
using a for loop, all the characters of string'c2'are copied at the
end of c1. return (c1) is
equivalent to
return&c1[0] and it returns the base address of'c1'.'finalstr'
stores that address returned by the
function strct().
16.Write a program to
delete a specified line from a text file.
In this program, user
is asked for a filename he needs to change. User is also asked for
the line number that is
to be deleted. The
filename is stored in'filename' . The file is opened and all the data
is transferre d to another file
except that one line
the user specifies to delete.
Program: Program to
delete a specific line.
#include
int main(){
FILE *fp1, *fp2;
// consider 40
character string to store filename
char filename[4 0];
char c;
int del_line, temp = 1;
//asks user for file
name
printf("En ter
file name:");
// receives file name
from user and stores in'filename'
scanf("%s" ,
filename);
//open file in read
mode
fp1 = fopen(file
name,"r");
c = getc(fp1);
//until the last
character of file is obtained
while (c != EOF)
{
printf("%c ",
c);
//print current
character and read next character
c = getc(fp1);
}
//rewind
rewind(fp1 );
printf("\n Enter
line number of the line to be deleted:") ;
//accept number from
user.
scanf("%d"
,&del_line) ;
//open new file in
write mode
fp2 = fopen("cop
y.c","w");
c = getc(fp1);
while (c != EOF){
c = getc(fp1);
if (c =='\n')
temp++;
//except the line to be
deleted
if (temp != del_line)
{
//copy all lines in
file copy.c
putc(c, fp2);
}
}
//close both the files.
fclose(fp1 );
fclose(fp2 );
//remove original file
remove(fil ename);
//rename the file
copy.c to original name
rename("co py.c",
filename);
printf("\n The
contents of file after being modified are as follows:\n ");
fp1 = fopen(file
name,"r");
c = getc(fp1);
while (c != EOF){
printf("%c ",
c);
c = getc(fp1);
}
fclose(fp1 );
return 0;
}
Output:
Enter file name:abc.t
xt
hi.
Hello
how are you?
I am fine
hope the same
Enter line number of
the line to be deleted:4
The contents of file
after being modified are as follows:
hi.
hello
how are you?
hope the same
Explanatio n:
In this program, user
is asked for a filename that needs to be modified. Entered file name
is stored in a char
array'filename' . This
file is opened in read mode using file pointer'fp1'. Character'c'is
used to read characters
from the file and print
them to the output. User is asked for the line number in the file to
be deleted. The file
pointer is rewinded
back and all the lines of the file except for the line to be deleted
are copied into another file
"copy.c".
Now"copy.c"is renamed to the original filename. The
original file is opened in read mode and the
modified contents of the file are displayed on the screen.
17.Write a program to
replace a specified line in a text file.
Program: Program to
replace a specified line in a text file.
#include
int main(void) {
FILE *fp1, *fp2;
// 'filename'i s a 40
character string to store filename
char filename[4 0];
char c;
int del_line, temp = 1;
//asks user for file
name
printf("En ter
file name:");
// receives file name
from user and stores in'filename'
scanf("%s" ,
filename);
fp1 = fopen(file
name,"r");
//open file in read
mode
c = getc(fp1);
//print the contents of
file .
while (c != EOF){
printf("%c ",
c);
c = getc(fp1);
}
//ask user for line
number to be deleted.
printf("\n Enter
line number to be deleted and replaced") ;
scanf("%d"
,&del_line) ;
//take fp1 to start
point.
rewind(fp1 );
//open copy.c in write
mode
fp2 = fopen("cop
y.c","w");
c = getc(fp1);
while (c != EOF){
if (c =='\n'){
temp++;
}
// till the line to be
deleted comes,copy the content from one file to other
if (temp != del_line){
putc(c, fp2);
}
else //when the line to
be deleted comes
{
while ((c = getc(fp1))
!='\n'){
}
//read and skip the
line ask for new text
printf("En ter new
text");
//flush the input
stream
fflush(std in);
putc('\n', fp2);
//put'\n'in new file
while ((c = getchar())
!='\n')
putc(c, fp2);
//take the data from
user and place it in new file
fputs("\n" ,
fp2);
temp++;
}
// continue this till
EOF is encountere d
c = getc(fp1);
}
//close both files
fclose(fp1 );
fclose(fp2 );
//remove original file
remove(fil ename);
//rename new file with
old name opens the file in read mode
rename("co py.c",
filename);
fp1 = fopen(file
name,"r");
//reads the character
from file
c = getc(fp1);
// until last character
of file is encountered
while (c != EOF){
printf("%c ",
c);
// all characters are
printed
c = getc(fp1);
}
//close the file
pointer
fclose(fp1 );
return 0;
}
Output:
Enter file name:abc.t
xt
hi.
hello
how are you?
hope the same
Enter line number of
the line to be deleted and replaced:4
Enter new text:
sayonara see you soon
hi.
hello
how are you?
sayonara see you soon
Explanatio n:
In this program, the
user is asked to type the name of the file. The File by name entered
by user is opened in
read mode. The line
number of the line to be replaced is asked as input. Next the data to
be replaced is asked. A
new file is opened in
write mode named"copy.c". Now the contents of original file
are transferre d into new file
and the line to be
modified is deleted. New data is stored in its place and remaining
lines of the original file are
also transferre d. The
copied file with modified contents is replaced with the original
file's name. Both the file
pointers are closed and
the original file is again opened in read mode and the contents of
the original file is
printed as output.
18.Write a program to
find the number of lines in a text file.
Number of lines in a
file can be determined by counting the number of new line characters
present.
Program: Program to
count number of lines in a file.
#include
int main()
/* Ask for a filename
and count number of lines in the file*/
{
//a pointer to a FILE
structure
FILE *fp;
int no_lines = 0;
// consider 40
character string to store filename
char filename[4 0],
sample_chr ;
//asks user for file
name
printf("En ter
file name:");
// receives file name
from user and stores in a string named'filename'
scanf("%s" ,
filename);
//open file in read
mode
fp = fopen(file
name,"r");
//get character from
file and store in sample_chr
sample_chr = getc(fp);
while (sample_ch r !=
EOF){
// Count whenever
sample_chr is'\n'(new line) is encountere d
if (sample_ch r =='\n')
{
// increment
variable'no_lines' by 1
no_lines=n o_lines+1;
}
//take next character
from file.
sample_chr = getc(fp);
}
fclose(fp) ; //close
file.
printf("Th ere are
%d lines in %s \n", no_lines, filename);
return 0;
}
Output:
Enter file name:abc.t
xt
There are 4 lines in
abc.txt
Explanatio n:
In this program, name
of the file to be read is taken as input. A file by the given name is
opened in read-mode
using a File
pointer'fp'. Characters from the file are read into a char
variable'sample_ch r'with the help of getc
function. If a new line
character( '\n') is encountere d, the integer variable'no_lines' is
incremente d. If the
character read
into'sample_ch ar'is not a new line character, next character is read
from the file. This process is
continued until the
last character of the file(EOF) is encountere d. The file pointer is
then closed and the total
number of lines is
shown as output.
19.Write a C program
which asks the user for a number between 1 to 9 and shows the number.
If the
user inputs a number
out of the specified range, the program should show an error and
prompt
the user for a valid
input.
Program: Program for
accepting a number in a given range.
#include
int getnumber( );
int main(){
int input = 0;
//call a function to
input number from key board
input = getnumber( );
//when input is not in
the range of 1 to 9,print error message
while (!((input = 1))){
printf("[E RROR]
The number you entered is out of range");
//input another number
input = getnumber( );
}
//this function is
repeated until a valid input is given by user.
printf("\n The
number you entered is %d", input);
return 0;
}/
/this function returns
the number given by user
int getnumber( ){
int number;
//asks user for a input
in given range
printf("\n Enter a
number between 1 to 9 \n");
scanf("%d"
,&number);
return (number);
}
Output:
Enter a number between
1 to 9
45
[ERROR] The number you
entered is out of range
Enter a number between
1 to 9
4
The number you entered
is 4
Explanatio n:
getfunctio n() function
accepts input from user.'while'loop checks whether the number falls
within range or not
and accordingl y either
prints the number(If the number falls in desired range) or shows
error message(number is
out of range).
20.Write a program to
display the multiplica tion table of a given number.
Program: Multiplica
tion table of a given number
#include
int main(){
int num, i = 1;
printf("\n Enter
any Number:");
scanf("%d"
,&num);
printf("Mu
ltiplicati on table of %d: \n", num);
while (i
printf("\n %d x %d
= %d", num, i, num * i);
i++;
}
return 0;
}
Output:
Enter any Number:5
5 x 1 = 5
5 x 2 = 10
5 x 3 = 15
5 x 4 = 20
5 x 5 = 25
5 x 6 = 30
5 x 7 = 35
5 x 8 = 40
5 x 9 = 45
5 x 10 = 50
Explanatio n:
We need to multiply the
given number (i.e. the number for which we want the multiplica tion
table)
with value of'i'which increments from 1 to 10.
21. .WAP to check a
string is Caliondrom e or not. // Maventic question.
#include
#include
void main()
{
int i,j=0; char a[100];
clrscr();
printf("\n Enter
the string to check for caliondrom e:\n");
gets(a);
if(strlen( a)%6)
{
printf("\n %s: is
Not a caliondrom e..",a);
getch();
exit(0);
}
for (i=0;a[i]! ='\0'
{
if((a[i]== a[i+5])&&(
a[i+1]==a[ i+4])&&(a[ i+2]==a[i+ 3]))
i=i+6;
else
{
j=1;
break;
}
}
if(j)
printf("\n %s: is
Not a caliondrom e..",a);
else
printf("\n %s: is
a caliondrom e..",a);
getch();
}
22.WAP to print
DONE,witho ut using any loop. // asked to my frnd in any company.
#include
void main()
{
static int i=0;
printf("\n %d.
DONE",i);
if(i++
main();
getch();
exit(0); / * I used
exit(0) to terminate the program after 100 DONE,,i dunno why it was
not terminating without using it,may be just at my system,try without
it at ur sustem,it sud work */
}
23.WAP to print
DONE,witho ut using any loop and any conditonal clause or operators.
/* This code is just in
purpose to solve the above question,, but its not a good code in
programmin g,as its terminatin g at divide error,,if anyone have a
better code,let me know */
main()
{
static int i=100;
printf("%d .
DONE\n",10 1-i);
main(1/ --i);
}
/*
use"ctrl+f9",then"alt+f5"to see the result */
24. WAP to find out the
longest word in a string.
#include
#include
#include
void main()
{
int i,max=0,co unt=0,j;
char str[100]; / *
={"INDIA IS DEMOCRATIC COUNTRY"}; u can use a string
inside,in place of user input */
printf("\n Enter
the string\n:" );
gets(str);
for(i=0;i
{
if(!(str[i ]==32))
{
count++;
}
else
{
if(max
{
j=i-count;
max=count;
}
count=0;
}
}
for(i=j;i
printf("%c
",str[i]);
getch();
}
25.Prog of WORLD MAP.
#include main(l
,a,n,d)cha r**a;{for(d=atoi (a[1])/ 10*80- atoi(a[2]) / 5-596;n="@N
KA\CLCCGZA AQBEAADAFa ISADJABBA^ \SNLGAQABD AXIMBAACTB ATAHDBAN\Z
cEMMCCCCAA hEIJFAEAAA BAfHJE\TBd FLDAANEfDN BPHdBcBBBE A_AL\ H E L L
O, W O R L D!"[l++-3];)f or(;n-->64 putchar(!d +++33^
l&1);print f("\n\n\n\ n\t\tFound By:\n\t\t\ t Amit
Aru");getc h();}
26.WAP to print the
triangle of letters in increasing order of lines.
#include
#include
void main()
{
int i,j,k;
char ch;
printf("\n Enter
the number of lines wants to make the triangle \n:");
scanf("%d"
,&i);
for(j=1;j
{
ch=65;
for(k=1;k
{
printf("%c
",ch++);
}
printf("\n ");
}
getch();
}
27.WAP to print'xay'in
place of every'a'in a string.
#include
#include
void main()
{
int i=0;
char str[100],x
='x',y='y' ;
printf("En ter the
string\n:");
gets(str);
while(str[ i]!='\0')
{
if(str[i]= ='a')
{
printf("%c ",x);
printf("%c
",str[i++] );
printf("%c ",y);
}
else
{
printf("%c
",str[i++] );
}
}
getch();
}
28.Count the Total
Number of 7 comming between 1 to 100.
#include
#include
void main()
{
int i,j,U=100,
L=1,count= 0,r=1,n;
clrscr();
printf("\n Enter
the number u wants to count\n:");
scanf("%d"
,&n);
printf("\n Enter
the lower limit\n:");
scanf("%d"
,&L);
printf("\n Enter
the upper limit\n:");
scanf("%d"
,&U);
for (i=L;i
{
j=i;
while(j)
{
r=j%10;
if (r==n)
{
count++;
}
j=j/10;
}
}
if(n==0&&L ==0)
count++;
printf("\n Total
Number of %d between %d and %d = %d",n,L,U, count);
getch();
}
29. Code for duplicate'
s removal,by Amit Aru.
#include
#include
void main()
{
int i,j,k=0,co
unt[300]={ 0};
char ch,str[100
0],str1[10 00];
clrscr();
printf("\n Enter
the string to remove duplicasy\ n:");
gets(str);
for (i=0;str[i
]!='\0';i+ +)
{
ch=str[i];
count['']=0; / * U can
use other delimiter inplace of space''here,just put that char
inside'',for ex: count['A']=0 ; if u dnt want any delimiter, just
remove this line.*/
if(count[c h])
continue;
else
{
str1[k++]= ch;
count[ch]= 1;
}
}
puts(str1) ;
getch();
}
30. WAP to find out if
a given number is a power series of 2 or not,withou t any loop and
without using % modulo operator.
#include
#include
int pow2(float );
void main()
{
int i,flag;
clrscr();
printf("En ter the
number\n") ;
scanf("%d"
,&i);
flag=pow2( i);
if(flag)
printf("\n %d is
power series of 2",i);
else
printf("\n %d is
not a power series of 2",i);
getch();
}
int pow2(float j)
{
static float x;
x=j/2;
if(x==2)
return 1;
if(x
return 0;
x=pow2(x);
}
:)
:(
:))
:((
=))
=D>
:D
:P
:-O
:-?
:-SS
:-f
d(
:-*
b-(
h-(
g-)
5-p
y-)
c-)
s-)
d-)
w-)
:-h
:X
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